IX
CHAPTER 9 Trigonometry

Trigonometry is a part of geometry that takes its origin in the ancient study of the relationship of the sides and angles of a right triangle. “Trigon” from Greek means triangle and “metron” means measure.
Applications of trigonometry are essential to many disciplines like carpentry, engineering, surveying, and astronomy, just to name a few.
How tall is the Riverpole? Do we have to climb the pole to find out? Fortunately, with the knowledge of trigonometry, we can find out the measurements of tall objects without too much hassle.
In this chapter we will explore the basic properties of angles and triangles, and the applications of the Pythagorean Theorem and trigonometric ratios.
52
9.1 Use Properties of Angles, Triangles, and the Pythagorean Theorem
Learning Objectives
By the end of this section, you will be able to:
- Use the properties of angles
- Use the properties of triangles
- Use the Pythagorean Theorem
Use the Properties of Angles
Are you familiar with the phrase ‘do a It means to make a full turn so that you face the opposite direction. It comes from the fact that the measure of an angle that makes a straight line is
degrees. See (Figure 1).
An angle is formed by two rays that share a common endpoint. Each ray is called a side of the angle and the common endpoint is called the vertex. An angle is named by its vertex. In (Figure 2), is the angle with vertex at point
. The measure of
is written
.

We measure angles in degrees, and use the symbol ° to represent degrees. We use the abbreviation to for the measure of an angle. So if
is 27°, we would write
.
If the sum of the measures of two angles is °, then they are called supplementary angles. In (Figure 3), each pair of angles is supplementary because their measures add to
°. Each angle is the supplement of the other.

If the sum of the measures of two angles is °, then the angles are complementary angles. In (Figure 4), each pair of angles is complementary, because their measures add to
°. Each angle is the complement of the other.

Supplementary and Complementary Angles
If the sum of the measures of two angles is °, then the angles are supplementary.
If and
are supplementary, then
°.
If the sum of the measures of two angles is °, then the angles are complementary.
If and
are complementary, then
°.
In this section and the next, you will be introduced to some common geometry formulas. We will adapt our Problem Solving Strategy for Geometry Applications. The geometry formula will name the variables and give us the equation to solve.
In addition, since these applications will all involve geometric shapes, it will be helpful to draw a figure and then label it with the information from the problem. We will include this step in the Problem Solving Strategy for Geometry Applications.
HOW TO: Use a Problem Solving Strategy for Geometry Applications
- Read the problem and make sure you understand all the words and ideas. Draw a figure and label it with the given information.
- Identify what you are looking for.
- Name what you are looking for and choose a variable to represent it.
- Translate into an equation by writing the appropriate formula or model for the situation. Substitute in the given information.
- Solve the equation using good algebra techniques.
- Check the answer in the problem and make sure it makes sense.
- Answer the question with a complete sentence.
The next example will show how you can use the Problem Solving Strategy for Geometry Applications to answer questions about supplementary and complementary angles.
EXAMPLE 1
An angle measures °. Find a) its supplement, and b) its complement.
| a) | |
| Step 1. Read the problem. Draw the figure and label it with the given information. | ![]() |
| Step 2. Identify what you are looking for. | ![]() |
| Step 3. Name. Choose a variable to represent it. | ![]() |
| Step 4. Translate. Write the appropriate formula for the situation and substitute in the given information. | ![]() ![]() |
| Step 5. Solve the equation. | ![]() |
Step 6. Check:![]() ![]() | |
| Step 7. Answer the question. | ![]() |
| b) | |
| Step 1. Read the problem. Draw the figure and label it with the given information. | ![]() |
| Step 2. Identify what you are looking for. | ![]() |
| Step 3. Name. Choose a variable to represent it. | ![]() |
| Step 4. Translate. Write the appropriate formula for the situation and substitute in the given information. | ![]() |
| Step 5. Solve the equation. | ![]() ![]() |
Step 6. Check:![]() ![]() | |
| Step 7. Answer the question. | ![]() |
TRY IT 1.1
An angle measures °. Find its: a) supplement b) complement.
- 155°
- 65°
TRY IT 1.2
An angle measures °. Find its: a) supplement b) complement.
- 103°
- 13°
Did you notice that the words complementary and supplementary are in alphabetical order just like and
are in numerical order?
EXAMPLE 2
Two angles are supplementary. The larger angle is ° more than the smaller angle. Find the measure of both angles.
Solution
| Step 1. Read the problem. Draw the figure and label it with the given information. | ![]() |
| Step 2. Identify what you are looking for. | ![]() |
| Step 3. Name. Choose a variable to represent it. The larger angle is 30° more than the smaller angle. | ![]() ![]() |
| Step 4. Translate. Write the appropriate formula and substitute. | ![]() |
| Step 5. Solve the equation. | ![]() ![]() ![]() ![]() ![]() ![]() ![]() |
Step 6. Check:![]() ![]() ![]() | |
| Step 7. Answer the question. | ![]() |
TRY IT 2.1
Two angles are supplementary. The larger angle is ° more than the smaller angle. Find the measures of both angles.
40°, 140°
TRY IT 2.2
Two angles are complementary. The larger angle is ° more than the smaller angle. Find the measures of both angles.
25°, 65°
Use the Properties of Triangles
What do you already know about triangles? Triangle have three sides and three angles. Triangles are named by their vertices. The triangle in (Figure 5) is called , read ‘triangle
’. We label each side with a lower case letter to match the upper case letter of the opposite vertex.

The three angles of a triangle are related in a special way. The sum of their measures is °.
Sum of the Measures of the Angles of a Triangle
For any , the sum of the measures of the angles is
°.
EXAMPLE 3
The measures of two angles of a triangle are ° and
°. Find the measure of the third angle.
Solution
| Step 1. Read the problem. Draw the figure and label it with the given information. | ![]() |
| Step 2. Identify what you are looking for. | ![]() |
| Step 3. Name. Choose a variable to represent it. | ![]() |
| Step 4. Translate. Write the appropriate formula and substitute. | ![]() |
| Step 5. Solve the equation. | ![]() ![]() ![]() |
Step 6. Check:![]() ![]() | |
| Step 7. Answer the question. | ![]() |
TRY IT 3.1
The measures of two angles of a triangle are ° and
°. Find the measure of the third angle.
21°
TRY IT 3.2
A triangle has angles of ° and
°. Find the measure of the third angle.
56°
Right Triangles
Some triangles have special names. We will look first at the right triangle. A right triangle has one ° angle, which is often marked with the symbol shown in (Figure 6).

If we know that a triangle is a right triangle, we know that one angle measures ° so we only need the measure of one of the other angles in order to determine the measure of the third angle.
EXAMPLE 4
One angle of a right triangle measures °. What is the measure of the third angle?
Solution
| Step 1. Read the problem. Draw the figure and label it with the given information. | ![]() |
| Step 2. Identify what you are looking for. | ![]() |
| Step 3. Name. Choose a variable to represent it. | ![]() |
| Step 4. Translate. Write the appropriate formula and substitute. | ![]() |
| Step 5. Solve the equation. | ![]() ![]() ![]() |
Step 6. Check:![]() ![]() | |
| Step 7. Answer the question. | ![]() |
TRY IT 4.1
One angle of a right triangle measures °. What is the measure of the other angle?
34°
TRY IT 4.2
One angle of a right triangle measures °. What is the measure of the other angle?
45°
In the examples so far, we could draw a figure and label it directly after reading the problem. In the next example, we will have to define one angle in terms of another. So we will wait to draw the figure until we write expressions for all the angles we are looking for.
EXAMPLE 5
The measure of one angle of a right triangle is ° more than the measure of the smallest angle. Find the measures of all three angles.
Solution
| Step 1. Read the problem. | |
| Step 2. Identify what you are looking for. | the measures of all three angles |
| Step 3. Name. Choose a variable to represent it. Now draw the figure and label it with the given information. | ![]() ![]() ![]() ![]() |
| Step 4. Translate. Write the appropriate formula and substitute into the formula. | ![]() ![]() |
| Step 5. Solve the equation. | ![]() ![]() ![]() ![]() ![]() ![]() ![]() |
Step 6. Check:![]() ![]() | |
| Step 7. Answer the question. | ![]() |
TRY IT 5.1
The measure of one angle of a right triangle is ° more than the measure of the smallest angle. Find the measures of all three angles.
20°, 70°, 90°
TRY IT 5.2
The measure of one angle of a right triangle is ° more than the measure of the smallest angle. Find the measures of all three angles.
30°, 60°, 90°
Similar Triangles
When we use a map to plan a trip, a sketch to build a bookcase, or a pattern to sew a dress, we are working with similar figures. In geometry, if two figures have exactly the same shape but different sizes, we say they are similar figures. One is a scale model of the other. The corresponding sides of the two figures have the same ratio, and all their corresponding angles are have the same measures.
The two triangles in (Figure 7) are similar. Each side of is four times the length of the corresponding side of
and their corresponding angles have equal measures.
and
are similar triangles. Their corresponding sides have the same ratio and the corresponding angles have the same measure.

Properties of Similar Triangles
If two triangles are similar, then their corresponding angle measures are equal and their corresponding side lengths are in the same ratio.

The length of a side of a triangle may be referred to by its endpoints, two vertices of the triangle. For example, in
We will often use this notation when we solve similar triangles because it will help us match up the corresponding side lengths.
EXAMPLE 6
and
are similar triangles. The lengths of two sides of each triangle are shown. Find the lengths of the third side of each triangle.

Solution
| Step 1. Read the problem. Draw the figure and label it with the given information. | The figure is provided. |
| Step 2. Identify what you are looking for. | The length of the sides of similar triangles |
| Step 3. Name. Choose a variable to represent it. | Let a = length of the third side of y = length of the third side |
| Step 4. Translate. | The triangles are similar, so the corresponding sides are in the same ratio. So Since the side Be careful to match up corresponding sides correctly.
|
| Step 5. Solve the equation. |
|
| Step 6. Check. | ![]() |
| Step 7. Answer the question. | The third side of |
TRY IT 6.1
is similar to
. Find
.

8
TRY IT 6.2
is similar to
. Find
.

22.5
Use the Pythagorean Theorem
The Pythagorean Theorem is a special property of right triangles that has been used since ancient times. It is named after the Greek philosopher and mathematician Pythagoras who lived around BCE.
Remember that a right triangle has a ° angle, which we usually mark with a small square in the corner. The side of the triangle opposite the
° angle is called the hypotenuse, and the other two sides are called the legs. See (Figure 8).
In a right triangle, the side opposite the ° angle is called the hypotenuse and each of the other sides is called a leg.

The Pythagorean Theorem tells how the lengths of the three sides of a right triangle relate to each other. It states that in any right triangle, the sum of the squares of the two legs equals the square of the hypotenuse.
The Pythagorean Theorem
In any right triangle ,
where is the length of the hypotenuse
and
are the lengths of the legs.

To solve problems that use the Pythagorean Theorem, we will need to find square roots. We defined the notation in this way:
For example, we found that is
because
.
We will use this definition of square roots to solve for the length of a side in a right triangle.
EXAMPLE 7
Use the Pythagorean Theorem to find the length of the hypotenuse.

Solution
| Step 1. Read the problem. | |
| Step 2. Identify what you are looking for. | the length of the hypotenuse of the triangle |
| Step 3. Name. Choose a variable to represent it. | Let ![]() |
| Step 4. Translate. Write the appropriate formula. Substitute. | ![]() |
| Step 5. Solve the equation. | ![]() |
Step 6. Check:![]() | |
| Step 7. Answer the question. | The length of the hypotenuse is 5. |
TRY IT 7.1
Use the Pythagorean Theorem to find the length of the hypotenuse.

10
TRY IT 7.2
Use the Pythagorean Theorem to find the length of the hypotenuse.

17
EXAMPLE 8
Use the Pythagorean Theorem to find the length of the longer leg.

Solution
| Step 1. Read the problem. | |
| Step 2. Identify what you are looking for. | The length of the leg of the triangle |
| Step 3. Name. Choose a variable to represent it. | Let Label side b ![]() |
| Step 4. Translate. Write the appropriate formula. Substitute. | ![]() |
| Step 5. Solve the equation. Isolate the variable term. Use the definition of the square root. Simplify. | ![]() |
| Step 6. Check: | ![]() |
| Step 7. Answer the question. | The length of the leg is 12. |
TRY IT 8.1
Use the Pythagorean Theorem to find the length of the leg.

8
TRY IT 8.2
Use the Pythagorean Theorem to find the length of the leg.

12
EXAMPLE 9
Kelvin is building a gazebo and wants to brace each corner by placing a wooden bracket diagonally as shown. How far below the corner should he fasten the bracket if he wants the distances from the corner to each end of the bracket to be equal? Approximate to the nearest tenth of an inch.

Solution
| Step 1. Read the problem. | |
| Step 2. Identify what you are looking for. | the distance from the corner that the bracket should be attached |
| Step 3. Name. Choose a variable to represent it. | Let x = the distance from the corner![]() |
| Step 4. Translate. Write the appropriate formula. Substitute. | ![]() |
| Step 5. Solve the equation. Isolate the variable. Use the definition of the square root. Simplify. Approximate to the nearest tenth. | ![]() |
Step 6. Check:![]() Yes. | |
| Step 7. Answer the question. | Kelvin should fasten each piece of wood approximately 7.1″ from the corner. |
TRY IT 9.1
John puts the base of a ladder
feet from the wall of his house. How far up the wall does the ladder reach?

12 feet
TRY IT 9.2
Randy wants to attach a string of lights to the top of the
mast of his sailboat. How far from the base of the mast should he attach the end of the light string?

8 feet
Key Concepts
- Supplementary and Complementary Angles
- If the sum of the measures of two angles is 180°, then the angles are supplementary.
- If
and
are supplementary, then
.
- If the sum of the measures of two angles is 90°, then the angles are complementary.
- If
and
are complementary, then
.
- Solve Geometry Applications
- Read the problem and make sure you understand all the words and ideas. Draw a figure and label it with the given information.
- Identify what you are looking for.
- Name what you are looking for and choose a variable to represent it.
- Translate into an equation by writing the appropriate formula or model for the situation. Substitute in the given information.
- Solve the equation using good algebra techniques.
- Check the answer in the problem and make sure it makes sense.
- Answer the question with a complete sentence.
Sum of the Measures of the Angles of a Triangle - For any
, the sum of the measures is 180°
- For any
Right Triangle - A right triangle is a triangle that has one 90° angle, which is often marked with a ⦜ symbol.
- Properties of Similar Triangles
- If two triangles are similar, then their corresponding angle measures are equal and their corresponding side lengths have the same ratio.
Glossary
- angle
- An angle is formed by two rays that share a common endpoint. Each ray is called a side of the angle.
- complementary angles
- If the sum of the measures of two angles is
°, then they are called complementary angles.
- hypotenuse
- The side of the triangle opposite the 90° angle is called the hypotenuse.
- legs of a right triangle
- The sides of a right triangle adjacent to the right angle are called the legs.
- right triangle
- A right triangle is a triangle that has one
° angle.
- similar figures
- In geometry, if two figures have exactly the same shape but different sizes, we say they are similar figures.
- supplementary angles
- If the sum of the measures of two angles is
°, then they are called supplementary angles.
- triangle
- A triangle is a geometric figure with three sides and three angles.
- vertex of an angle
- When two rays meet to form an angle, the common endpoint is called the vertex of the angle.
Practice Makes Perfect
Use the Properties of Angles
In the following exercises, find a) the supplement and b) the complement of the given angle.
| 1. | 2. |
| 3. | 4. |
In the following exercises, use the properties of angles to solve.
| 5. Find the supplement of a | 6. Find the complement of a |
| 7. Find the complement of a | 8. Find the supplement of a |
| 9. Two angles are supplementary. The larger angle is | 10. Two angles are supplementary. The smaller angle is |
| 11. Two angles are complementary. The smaller angle is | 12. Two angles are complementary. The larger angle is |
Use the Properties of Triangles
In the following exercises, solve using properties of triangles.
| 13. The measures of two angles of a triangle are | 14. The measures of two angles of a triangle are |
| 15. The measures of two angles of a triangle are | 16. The measures of two angles of a triangle are |
| 17. One angle of a right triangle measures | 18. One angle of a right triangle measures |
| 19. One angle of a right triangle measures | 20. One angle of a right triangle measures |
| 21. The two smaller angles of a right triangle have equal measures. Find the measures of all three angles. | 22. The measure of the smallest angle of a right triangle is |
| 23. The angles in a triangle are such that the measure of one angle is twice the measure of the smallest angle, while the measure of the third angle is three times the measure of the smallest angle. Find the measures of all three angles. | 24. The angles in a triangle are such that the measure of one angle is |
Find the Length of the Missing Side
In the following exercises, is similar to
. Find the length of the indicated side.

| 25. side | 26. side |
On a map, San Francisco, Las Vegas, and Los Angeles form a triangle whose sides are shown in the figure below. The actual distance from Los Angeles to Las Vegas is miles.

| 27. Find the distance from Los Angeles to San Francisco. | 28. Find the distance from San Francisco to Las Vegas. |
Use the Pythagorean Theorem
In the following exercises, use the Pythagorean Theorem to find the length of the hypotenuse.
29. ![]() | 30. ![]() |
31. ![]() | 32. ![]() |
Find the Length of the Missing Side
In the following exercises, use the Pythagorean Theorem to find the length of the missing side. Round to the nearest tenth, if necessary.
33. ![]() | 34. ![]() |
35. ![]() | 36. ![]() |
37. ![]() | 38. ![]() |
39. ![]() | 40. ![]() |
In the following exercises, solve. Approximate to the nearest tenth, if necessary.
41. A
| 42. Pam wants to put a banner across her garage door to congratulate her son on his college graduation. The garage door is
|
43. Chi is planning to put a path of paving stones through her flower garden. The flower garden is a square with sides of
| 44. Brian borrowed a
|
Everyday Math
| 45. Building a scale model Joe wants to build a doll house for his daughter. He wants the doll house to look just like his house. His house is | 46. Measurement A city engineer plans to build a footbridge across a lake from point
|
Writing Exercises
| 47. Write three of the properties of triangles from this section and then explain each in your own words. | 48. Explain how the figure below illustrates the Pythagorean Theorem for a triangle with legs of length
|
Answers
| 1. a) 127° b) 37° | 3. a) 151° b) 61° | 5. 45° |
| 7. 62.5° | 9. 62°, 118° | 11. 62°, 28° |
| 13. 56° | 15. 44° | 17. 57° |
| 19. 67.5° | 21. 45°, 45°, 90° | 23. 30°, 60°, 90° |
| 25. 12 | 27. 351 miles | 29. 15 |
| 31. 25 | 33. 8 | 35. 12 |
| 37. 10.2 | 39. 8 | 41. 5 feet |
| 43. 14.1 feet | 45. 2.9 feet | 47. Answers will vary. |
Attributions
This chapter has been adapted from “Use Properties of Angles, Triangles, and the Pythagorean Theorem” in Prealgebra (OpenStax) by Lynn Marecek, MaryAnne Anthony-Smith, and Andrea Honeycutt Mathis, which is under a CC BY 4.0 Licence. Adapted by Izabela Mazur. See the Copyright page for more information.
53
9.2 Solve Applications: Sine, Cosine and Tangent Ratios.
Learning Objectives
By the end of this section, you will be able to:
- Find missing side of a right triangle using sine, cosine, or tangent ratios
- Find missing angle of a right triangle using sine, cosine, or tangent ratios
- Solve applications using right angle trigonometry
Sine, Cosine, and Tangent Ratios
We know that any right triangle has three sides and a right angle. The side opposite to the right angle is called the hypotenuse. The other two angles in a right triangle are acute angles (with a measure less than 90 degrees). One of those angles we call reference angle and we use θ (theta) to represent it.
The hypotenuse is always the longest side of a right triangle. The other two sides are called opposite side and adjacent side. The names of those sides depends on which of the two acute angles is being used as a reference angle.

In the right triangle each side is labeled with a lowercase letter to match the uppercase letter of the opposite vertex.
EXAMPLE 1
Label the sides of the triangle and find the hypotenuse, opposite, and adjacent.

Solution
We labeled the sides with a lowercase letter to match the uppercase letter of the opposite vertex.
c is hypotenuse
a is opposite
b is adjacent

TRY IT 1.1
Label the sides of the triangle and find the hypotenuse, opposite and adjacent.

y is hypotenuse
z is opposite
x is adjacent
TRY IT 1.2
Label the sides of the triangle and find the hypotenuse, opposite and adjacent.

r is hypotenuse
t is opposite
s is adjacent
Trigonometric Ratios
Trigonometric ratios are the ratios of the sides in the right triangle. For any right triangle we can define three basic trigonometric ratios: sine, cosine, and tangent.
Let us refer to Figure 1 and define the three basic trigonometric ratios as:
Three Basic Trigonometric Ratios
- sine θ =
- cosine θ =
- tangent θ =
Where θ is the measure of a reference angle measured in degrees.
Very often we use the abbreviations for sine, cosine, and tangent ratios.
- sin θ =
- cos θ =
- tan θ =
Some people remember the definition of the trigonometric ratios as SOH CAH TOA.
Let’s use the from Example 1 to find the three ratios.
EXAMPLE 2
For the given triangle find the sine, cosine and tangent ratio.

Solution
sin θ =
cos θ =
tan θ =
TRY IT 2.1
For the given triangle find the sine cosine and tangent ratio.

sin θ =
cos θ =
tan θ =
TRY IT 2.2
For the given triangle find the sine, cosine and tangent ratio.

sin θ =
cos θ =
tan θ =
In Example 2, our reference angles can be or
. Using the definition of trigonometric ratios, we can write sinE=
, cosE=
, and tanE=
.
When calculating we will usually round the ratios to four decimal places and at the end our final answer to one decimal place unless stated otherwise.
EXAMPLE 3
For the given triangle find the sine, cosine and tangent ratios. If necessary round to four decimal places.

Solution
We have two possible reference angles: R an S.
Using the definitions, the trigonometric ratios for angle R are:
- sin R=
= 0.8
- cos R=
= 0.6
- tan R=
= 1.3333…
Using the definitions, the trigonometric ratios for angle S:
- sin S =
= 0.6
- cos S =
= 0.8
- tan S =
= 0.75
TRY IT 3.1
For the given triangle find the sine, cosine, and tangent ratios. If necessary round to four decimal places.

- sin F =
= 0.8
- cos F =
=0.6
- tan F =
= 1.3333…
- sin D =
= 0.6
- cos D =
= 0.8
- tan D =
= 0.75
TRY IT 3.2
For given triangle find the sine, cosine and tangent ratios. If necessary round to four decimal places.

- sin A =
= 0.8621
- cos A =
=0.5172
- tan A =
= 1.6667
- sin C =
= 0.5172
- cos C =
= 0.8621
- tan C =
= 0.6
Now, let us use a scientific calculator to find the trigonometric ratios. Can you find the sin, cos, and tan buttons on your calculator? To find the trigonometric ratios make sure your calculator is in Degree Mode.
EXAMPLE 4
Using a calculator find the trigonometric ratios. If necessary, round to 4 decimal places.
a) sin 30°
b) cos 45°
c) tan 60°
Solution
Make sure your calculator is in Degree Mode.
a) Using a calculator find that sin 30° = 0.5
b) Using a calculator find that cos 45° = 0.7071 Rounded to 4 decimal places.
c) Using a calculator find that tan 60° = 1.7321 Rounded to 4 decimal places.
TRY IT 4.1
Find the trigonometric ratios. If necessary, round to 4 decimal places.
a) sin 60°
b) cos 30°
c) tan 45°
a) sin 60° = 0.8660
b) cos 30° = 0.8660
c) tan 45° = 1
TRY IT 4.2
Find the trigonometric ratios. If necessary, round to 4 decimal places.
a) sin 35°
b) cos 67°
c) tan 83°
a) sin 35° = 0.5736
b) cos 67 ° = 0.3907
c) tan 83° = 8.1443
Finding Missing Sides of a Right Triangle
In this section you will be using trigonometric ratios to solve right triangle problems. We will adapt our problem solving strategy for trigonometry applications. In addition, since those problems will involve the right triangle, it is helpful to draw it (if the drawing is not given) and label it with the given information.We will include this in the first step of the problem solving strategy for trigonometry applications.
HOW TO: Solve Trigonometry Applications
- Read the problem and make sure all the words and ideas are understood. Draw the right triangle and label the given parts.
- Identify what we are looking for.
- Label what we are looking for by choosing a variable to represent it.
- Find the required trigonometric ratio.
- Solve the ratio using good algebra techniques.
- Check the answer by substituting it back into the ratio in step 4 and by making sure it makes sense in the context of the problem.
- Answer the question with a complete sentence.
In the next few examples, having given the measure of one acute angle and the length of one side of the right triangle, we will solve the right triangle for the missing sides.
EXAMPLE 5
Find the missing sides. Round your final answer to two decimal places

Solution
| 1. Read the problem and make sure all the words and ideas are understood. Draw the right triangle and label the given parts. | A drawing is given. Angle Y is our reference angle, y is opposite side, z is adjacent side, and x=14 is the hypotenuse. | |
| 2. Identify what we are looking for. | a) the opposite side | b) adjacent side |
| 3.Label what we are looking for by choosing a variable to represent it. | y=? | z=? |
| 4. Find the required trigonometric ratio. | sin 35° = | cos 35° = |
| 5. Solve the ratio using good algebra techniques. | 14 sin 35° = y 8.03 = y | 14 cos 35° = z 11.47 = z |
| 6. Check the answer in the problem and by making sure it makes sense. | 0.57 0.57 = 0.57 | 0.82 0.82 = 0.82 |
| 7. Answer the question with a complete sentence. | The opposite side is 8.03 | The adjacent side is 11.47 |
TRY IT 5.1
Find the missing sides. Round your final answer to one decimal place.

a = 20.2
b = 16.4
TRY IT 5.2
Find the missing sides. Round your final answer to one decimal place.

d = 3.4
f = 9.4
EXAMPLE 6
Find the hypotenuse. Round your final answer to one decimal place.

Solution
| 1. Read the problem and make sure all the words and ideas are understood. Draw the right triangle and label the given parts. | A drawing is given. Angle S is our reference angle, s is opposite side, r = 4 is the adjacent side, and p is the hypotenuse |
| 2. Identify what we are looking for. | the hypotenuse |
| 3.Label what we are looking for by choosing a variable to represent it. | p=? |
| 4. Find the required trigonometric ratio. | cos 32° = |
| 5. Solve the ratio using good algebra techniques. | 0.8480 = p = 4.7170 Rounding the ratios to 4 decimal places |
| 6. Check the answer in the problem and by making sure it makes sense. | 0.8480 0.8480 = 0.8480 |
| 7. Answer the question with a complete sentence. | The hypotenuse is 4.7 Round my final answer to one decimal place. |
TRY IT 6.1..
Find the hypotenuse. Round your final answer to one decimal place.

p = 22.7
TRY IT 6.2
Find the hypotenuse. Round your final answer to one decimal place.

p = 6.5
Finding Missing Angles of a Right Triangle
Sometimes we have a right triangle with only the sides given. How can we find the missing angles? To find the missing angles, we use the inverse of the trigonometric ratios. The inverse buttons sin-1, cos-1, and tan-1 are on your scientific calculator.
EXAMPLE 7
Find the angles. Round your final answer to one decimal place.
a) sin A = 0.5
b) cos B = 0.9735
c) tan C = 2.89358
Solution
Use your calculator and press the 2nd FUNCTION key and then press the SIN, COS, or TAN key
a) A = sin-10.5
= 30°
b) B = cos-10.9735
= 13.2° Rounded to one decimal place
c) C = tan-12.89358
= 70.9° Rounded to one decimal place
TRY IT 7.1
Find the angles. Round your final answer to one decimal place.
a) sin X = 1
b) cos Y = 0.375
c) tan Z = 1.676767
a) = 90°
b) = 68°
c) = 59.2°
TRY IT 7.2
Find the angles. Round your final answer to one decimal place.
a) sin C = 0
b) cos D = 0.95
c) tan F = 6.3333
a) = 0°
b) = 18.2°
c) = 81°
In the example below we have a right triangle with two sides given. Our acute angles are missing. Let us see what the steps are to find the missing angles.
EXAMPLE 8
Find the missing . Round your final answer to one decimal place.

Solution
| 1. Read the problem and make sure all the words and ideas are understood. Draw the right triangle and label the given parts. | A drawing is given. Angle T is our reference angle, t = 7 is the opposite side, s is adjacent side, and r =11 is the hypotenuse |
| 2. Identify what we are looking for. | angle T |
| 3.Label what we are looking for by choosing a variable to represent it. | |
| 4. Find the required trigonometric ratio. | sin T = |
| 5. Solve the ratio using good algebra techniques. | sin T = 0.6364 T = sin-10.6364
|
| 6. Check the answer in the problem and by making sure it makes sense. | sin 39.5239° 0.6364 = 0.6364 |
| 7. Answer the question with a complete sentence. | The missing angle T is 39.5°. |
TRY IT 8.1
Find the missing angle X. Round your final answer to one decimal place.

20.1°
TRY IT 8.2
Find the missing angle Z. Round your final answer to one decimal place.

69.9°
EXAMPLE 9
Find the missing angle A. Round your final answer to one decimal place.

Solution
| 1. Read the problem and make sure all the words and ideas are understood. Draw the right triangle and label the given parts. | A drawing is given. Angle A is our reference angle, a = 9 is the opposite side, c = 5 is the adjacent side, and b is the hypotenuse |
| 2. Identify what we are looking for. | angle A |
| 3.Label what we are looking for by choosing a variable to represent it. | |
| 4. Find the required trigonometric ratio. | tan A = |
| 5. Solve the ratio using good algebra techniques. | tan A = 1.8 A = tan-1 1.8
|
| 6. Check the answer in the problem and by making sure it makes sense. | tan 60.9° 1.8 = 1.8 |
| 7. Answer the question with a complete sentence. | The missing angle A is 60.9°. |
TRY IT 9.1
Find the missing angle C. Round your final answer to one decimal place.

29.1°
TRY IT 9.2
Find the missing angle E. Round your final answer to one decimal place.

36.9°
Solving a Right Triangle
From the section before we know that any triangle has three sides and three interior angles. In a right triangle, when all six parts of the triangle are known, we say that the right triangle is solved.
EXAMPLE 10
Solve the right triangle. Round your final answer to one decimal place.

Solution
Since the sum of angles in any triangle is 180°, the measure of angle B can be easy calculated.
= 180° − 90° − 42°
= 48°
| 1. Read the problem and make sure all the words and ideas are understood. Draw the right triangle and label the given parts. | A drawing is given. Angle A is our reference angle, a = 8 is the opposite side, b is the adjacent side, and c is the hypotenuse. | |
| 2. Identify what we are looking for. | a) adjacent side | b) hypotenuse |
| 3.Label what we are looking for by choosing a variable to represent it. | b = ? | c = ? |
| 4. Find the required trigonometric ratio. | tan 42° = | sin 42° = |
| 5. Solve the ratio using good algebra techniques. | 0.9004 = 0.9004 b = 8 b = 8.8849 | 0.6691 = 0.6691 c = 8 c = 11.9563 |
| 6. Check the answer in the problem and by making sure it makes sense. | tan 42 ° 0.9 = 0.9 | sin 42° 0.6691 = 0.6691 |
| 7. Answer the question with a complete sentence. | The adjacent side is 8.9. Rounded to one decimal place. | The hypotenuse is 12 |
We solved the right triangle
= 42°
= 48°
= 90°
a = 8
b = 8.9
c = 12
TRY IT 10.1
Solve the right triangle. Round your final answer to one decimal place.

= 21°
= 69°
= 90°
a = 6
b = 15.6
c = 16.7
TRY IT 10.2
Solve the right triangle. Round your final answer to one decimal place.

=16°
= 74°
= 90°
a = 2.9
b = 10
c = 10.4
EXAMPLE 11
Solve the right triangle. Round to two decimal places.

Solution
| 1. Read the problem and make sure all the words and ideas are understood. Draw the right triangle and label the given parts. | A drawing is given. Let angle D be our reference angle, d = 4 is the opposite side, f is the adjacent side, and e = 9 is the hypotenuse | |
| 2. Identify what we are looking for. | a) angle D | b) adjacent |
| 3.Label what we are looking for by choosing a variable to represent it. | f = ? | |
| 4. Find the required trigonometric ratio. | sin D = | 42 + f2 = 92 |
| 5. Solve the ratio using good algebra techniques. | sin D = 0.4444 D = sin-10.4444
| 16 + f2 = 81 f2 = 81 – 16 f2 = 65 f = square root of 65 f = 8.06 |
| 6. Check the answer in the problem and by making sure it makes sense. | sin 26.3850° 0.4444 =0.4444 | 42 + 8.062 81 = 81 |
| 7. Answer the question with a complete sentence. | The missing angle D is 26.39°. | The adjacent side is 8.06 Rounded to two decimal places |
The missing angle F = 180° – 90° – 26.39° = 63.64°
We solved the right triangle
= 26.39°
= 90°
= 63.61°
d = 4
e = 9
f = 8.06
TRY IT 11.1
Solve the right triangle. Round to one decimal place.

= 29.3°
= 90°
= 60.7°
d = 29.4
e = 18.4
f = 60.6
TRY IT 11.2
Solve the right triangle. Round to one decimal place.

= 45.6°
= 90°
= 44.4°
d = 7.1
e = 10
f = 7
Solve Applications Using Trigonometric Ratios
In the previous examples we were able to find missing sides and missing angles of a right triangle. Now, let’s use the trigonometric ratios to solve real-life problems.
Many applications of trigonometric ratios involve understanding of an angle of elevation or angle of depression.
The angle of elevation is an angle between the horizontal line (ground) and the observer’s line of sight.

The angle of depression is the angle between horizontal line (that is parallel to the ground) and the observer’s line of sight.

EXAMPLE 12
James is standing 31 metres away from the base of the Harbour Centre in Vancouver. He looks up to the top of the building at a 78° angle. How tall is the Harbour Centre?
Solution
| 1. Read the problem and make sure all the words and ideas are understood. Draw the right triangle and label the given parts. | Angle X is our reference angle, x is opposite side, y = 31 m is the adjacent side, and z is the hypotenuse. |
| 2. Identify what we are looking for. | The opposite side |
| 3.Label what we are looking for by choosing a variable to represent it. | x=? |
| 4. Find the required trigonometric ratio. | tan 78° = |
| 5. Solve the ratio using good algebra techniques. | 4.7046 = x = 145.8426 |
| 6. Check the answer in the problem and by making sure it makes sense. | 4.7046 4.7046 = 4.7046 |
| 7. Answer the question with a complete sentence. | The Harbour Centre is 145.8426 metres or rounded to 146 metres. |
TRY IT 12.1
Nicole is standing 75 feet away from the base of the Living Shangri-La, the tallest building in British Columbia. She looks up to the top of the building at a 83.5° angle. How tall is the Living Shangri-La?
658.3 feet.
TRY IT 12.2
Kelly is standing 23 metres away from the base of the tallest apartment building in Prince George and looks at the top of the building at a 62° angle. How tall is the building?
43.3 metres
EXAMPLE 13
Thomas is standing at the top of the building that is 45 metres high and looks at his friend that is standing on the ground, 22 metres from the base of the building. What is the angle of depression?
Solution
| 1. Read the problem and make sure all the words and ideas are understood. Draw the right triangle and label the given parts. |
Angle Y is our reference angle, y = 45 m is the opposite side, z = 22 m is the adjacent side, and x is the hypotenuse |
| 2. Identify what we are looking for. | angle Y |
| 3.Label what we are looking for by choosing a variable to represent it. | |
| 4. Find the required trigonometric ratio. | tan Y = |
| 5. Solve the ratio using good algebra techniques. | tan Y = 2.0455 Y = tan –¹2.0455
|
| 6. Check the answer in the problem and by making sure it makes sense. | tan 63.9470° 2.0455 = 2.0455 |
| 7. Answer the question with a complete sentence. | The angle of depression is 63.9470° or 64° rounded to one decimal place. |
TRY IT 13.1
Hemanth is standing on the top of a cliff 250 feet above the ground and looks at his friend that is standing on the ground, 40 feet from the base of the cliff. What is the angle of depression?
80.9°
TRY IT 13.2
Klaudia is standing on the ground, 25 metres from the base of the cliff and looks up at her friend on the top of a cliff 100 metres above the ground. What is the angle of elevation?
76°
Key Concepts
- Three Basic Trigonometric Ratios: (Where θ is the measure of a reference angle measured in degrees.)
- sine θ =
- cosine θ =
- tangent θ =
- sine θ =
- Problem-Solving Strategy for Trigonometry Applications
- Read the problem and make sure all the words and ideas are understood. Draw the right triangle and label the given parts.
- Identify what we are looking for.
- Label what we are looking for by choosing a variable to represent it.
- Find the required trigonometric ratio.
- Solve the ratio using good algebra techniques.
- Check the answer by substituting it back into the ratio solved in step 5 and by making sure it makes sense in the context of the problem.
- Answer the question with a complete sentence.
Practice Makes Perfect
Label the sides of the triangle.
| 1
| 2.
|
| 3. If the reference angle in Question 1 is B, Find the adjacent ?
| 4. If the reference angle in Question 2 is Z, find the opposite ? |
Label the sides of the triangle and find the hypotenuse, opposite and adjacent.
5.![]() | 6.![]() |
Use your calculator to find the given ratios. Round to four decimal places if necessary:
| 7. | 8. |
| 9. | 10. |
For the given triangles, find the sine, cosine and tangent of the θ.
11. ![]() | 12. ![]() |
13. ![]() | 14. ![]() |
For the given triangles, find the missing side. Round it to one decimal place.
15. Find the hypotenuse.![]() | 16. Find b if a = 6. ![]() |
17. Find the opposite. ![]() | 18. Find the adjacent. ![]() |
For the given triangles, find the missing sides. Round it to one decimal place.
19. ![]() | 20. ![]() |
Solve the triangles. Round to one decimal place.
21. ![]() | 22. ![]() |
23. ![]() | 24. ![]() |
| 25. A surveyor stands 75 metres from the bottom of a tree and looks up at the top of the tree at a 48° angle. How tall is the tree? | 26. A tree makes a shadow that is 6 metres long when the angle of elevation to the sun is 52°. How tall is the tree? |
| 27. A ladder that is 15 feet is leaning against a house and makes a 45° angle with the ground. How far is the base of the ladder from the house? | 28. Matt is flying a kite and has let out 100 feet of string. The angle of elevation with the ground is 38°. How high is his kite above the ground? |
| 29. Marta is flying a kite and has let out 28 metres of string. If the kite is 10 metres above the ground, what is the angle of elevation? | 30. An airplane takes off from the ground at the angle of 25°. If the airplane traveled 200 kilometres, how high above the ground is it? |
Answers
| 1.
| 3. c | 5.
g is opposite , f is adjacent, and e is hypotenuse |
| 7. 0.7314 | 9. 0.2126 | 11.
sin θ = |
| 13. sin θ = | 15. b = 19.8 | 17. c = 12 |
| 19. y = 19.3, z = 8.2 | 21.
b = 38.5 c = 21.3 d = 44 | 23.
t = 15 r = 25 s = 20 |
| 25. 83.3 m | 27. 10.6 ft | 29. 20.9° |
54
9.3 Chapter Review
Review Exercises
Use Properties of Angles
In the following exercises, solve using properties of angles.
| 1. What is the supplement of a | 2. What is the complement of a |
| 3. Two angles are complementary. The smaller angle is | 4. Two angles are supplementary. The larger angle is |
Use Properties of Triangles
In the following exercises, solve using properties of triangles.
| 5. The measures of two angles of a triangle are | 6. One angle of a right triangle measures |
| 7. One angle of a triangle is | 8. One angle of a triangle is twice the measure of the smallest angle. The third angle is |
In the following exercises, is similar to
. Find the length of the indicated side.

| 9. side | 10. side |
Use the Pythagorean Theorem
In the following exercises, use the Pythagorean Theorem to find the length of the missing side. Round to the nearest tenth, if necessary.
11. ![]() | 12. ![]() |
13. ![]() | 14. ![]() |
15. ![]() | 16. ![]() |
17. Sergio needs to attach a wire to hold the antenna to the roof of his house, as shown in the figure. The antenna is
| 18. Seong is building shelving in his garage. The shelves are
|
Find missing side of a right triangle using sine, cosine, or tangent ratios.
| 19. Label the triangle and find the sine cosine and tangent of θ.
| 20. If reference angle in above triangle is angle T, label the triangle and find the sine, cosine, and tangent of T. |
Find missing angle of a right triangle using sine, cosine, or tangent ratios.
| 21. Find angle M
| 22. Find angle L.
|
Solve the right triangle.
| 23. Solve the triangle.
| 24.
|
Solve applications using right angle trigonometry.
25. A 13-foot string of lights will be attached to the top of a 12-foot pole for a holiday display, as shown below. What is the angle that the string of lights makes with the ground?
| 26. Brian borrowed a 20 foot extension ladder to use when he paints his house. If he sets the base of the ladder 6 feet from the house, as shown below, what is the angle that the ladder makes with the ground?
|
27. John puts the base of a 13-foot ladder five feet from the wall of his house as shown below. What is the angle between the top of the ladder and the house ?
| 28. The sun is at an angle of elevation of 35°. If Bob casts a shadow that is 6 ft long, how tall is Bob? |
| 29. A 27 foot guy wire to a pole makes an angle of 63.7° with the ground. How high from the ground is the wire attached to the pole? | 30. A lighthouse is 20 metres tall. If the observer is looking at a boat that is 30 metres away from the base of the lighthouse, what is the angle of depression? |
Review Answers
| 1. 132° | 3. 33°, 57° | 5. 73° |
| 7. 30°, 60°, 90° | 9. 15 | 11. 26 |
| 13. 8 | 15. 8.1 | 17. 6 feet |
| 19.
sin θ = | 21. 55.2° | 23. |
| 25. 67.4° | 27. 22.6° | 29. 24 |
Practice Test
| 1. What is the supplement of a | 2. Two angles are complementary. The smaller angle is |
| 3. The measures of two angles of a triangle are | 4.
|
| 5. Use the Pythagorean Theorem to find the length of the missing side. Round to the nearest tenth, if necessary.
| 6. Find the hypotenuse.
|
7. Find angle G.
| 8. Solve the triangle.
|
| 9. The sun is at an angle 28°. If Adam casts a shadow that is 7 ft long, how tall is Adam? | 10. The road rises 6 metres per every 100 horizontal metres. What is the angle of elevation. |
Answers
| 1. 123° | 2. 53°, 37° | 3. 76° |
| 4. b = 14, t = 7.5 | 5. b = 15.3 | 6. d = 18.4 |
| 7. | 8. | 9. 5.5 ft |
| 10. 3.4° |
1
Acknowledgements
It is my genuine pleasure to express many thanks and gratitude to the people who have significantly contributed to my accomplishment:
- Krista Lambert for her remarkable and endless support, advice, and encouragement throughout this project.
- Josie Gray, Harper Friedman, and Kaitlyn Zheng for providing astounding technical support in completing, reviewing, and publishing this open textbook.
- Hemanth Anil and Kimberly Lebel for their wonderful contribution, dedication, and time spent on formatting of the textbook.
- Thompson Rivers University administration and employees for their ongoing support of Open Educational Resources.
2
Versioning History
This page provides a record of edits and changes made to this book since its initial publication. Whenever edits or updates are made in the text, we provide a record and description of those changes here. If the change is minor, the version number increases by 0.01. If the edits involve substantial updates, the version number increases to the next full number.
The files posted by this book always reflect the most recent version. If you find an error in this book, please fill out the Report an Error form.
| Version | Date | Change | Details |
|---|---|---|---|
| 1.01 | March 26, 2021 | Book published | |
| 1.02 | May 19, 2021 | Acknowledgements section added to the front matter. | |
| 1.03 | November 17, 2021 | Corrections made to Chapter 9.2 | Solutions for TRY IT 11.1 altered, questions for Exercise 16 and 22 altered. |
| 1.04 | September 12, 2025 | Corrections made to chapters 2.1 and 2.2 | Solution for TRY IT 10.2 in chapter 2.1 was corrected. Questions for TRY IT 4.1 and TRY IT 8.1 in chapter 2.2 were altered. |















































































































































